Which of the followin compounds will give a yellow precipitate with iodine and alkali?

Options

A. Acetophenoone
B. Methyl acetate
C. Acetamide
D. 2-Hydroxypropane

Explanation

To determine which compounds will give a yellow precipitate with iodine and alkali, we need to identify the presence of methyl ketone or methyl alcohol groups in the given options. The yellow precipitate is indicative of the iodoform test.

### Step-by-Step Solution:

1. **Understand the Iodoform Test**: The iodoform test is a chemical reaction that identifies the presence of methyl ketones (RCOCH3) or methyl alcohols (RCH(OH)CH3) in a compound. When these compounds react with iodine (I2) in the presence of a base (alkali), they produce a yellow precipitate of iodoform (CHI3).

2. **Analyze Each Option**:
- **Option 1: Acetophenone (C6H5COCH3)**
- Structure: CH3C(=O)C6H5
- This compound contains a methyl ketone group (COCH3).
- **Conclusion**: It will give a yellow precipitate with iodine and alkali.

- **Option 2: Methyl Acetate (CH3COOCH3)**
- Structure: CH3C(=O)OCH3
- This compound is an ester and does not have a methyl ketone or methyl alcohol group.
- **Conclusion**: It will not give a yellow precipitate.

- **Option 3: Acetamide (CH3CONH2)**
- Structure: CH3C(=O)NH2
- This compound is an amide and does not have a methyl ketone or methyl alcohol group.
- **Conclusion**: It will not give a yellow precipitate.

- **Option 4: 2-Hydroxypropane (Isopropyl Alcohol or Propan-2-ol)**
- Structure: CH3CHOHCH3
- This compound contains a methyl alcohol group (RCH(OH)CH3).
- **Conclusion**: It will give a yellow precipitate with iodine and alkali.

3. **Final Answer**: The compounds that will give a yellow precipitate with iodine and alkali are:
- Option 1: Acetophenone
- Option 4: 2-Hydroxypropane

### Summary of Results:
- **Correct Options**: 1 and 4 (Acetophenone and 2-Hydroxypropane)