The toal number of structural isomeric alcohols having the molecular `C_(5)H_(12)O` is.

Explanation

To determine the total number of structural isomeric alcohols with the molecular formula C5H12O, we can follow these steps:

### Step 1: Analyze the Molecular Formula
The molecular formula C5H12O indicates that we have 5 carbon atoms, 12 hydrogen atoms, and 1 oxygen atom. Since it is an alcohol, the functional group -OH (hydroxyl group) is present.

### Step 2: Determine the Degree of Unsaturation
The degree of unsaturation can be calculated using the formula:
\[ \text{Degree of Unsaturation} = \frac{(2C + 2 + N - H - X)}{2} \]
Where:
- C = number of carbons
- H = number of hydrogens
- N = number of nitrogens (not applicable here)
- X = number of halogens (not applicable here)

For C5H12O:
- C = 5
- H = 12
- N = 0
- X = 0

Plugging in the values:
\[ \text{Degree of Unsaturation} = \frac{(2 \times 5 + 2 - 12)}{2} = \frac{(10 + 2 - 12)}{2} = \frac{0}{2} = 0 \]

This indicates that there are no rings or double bonds in the structure.

### Step 3: Identify Possible Structures
Since the degree of unsaturation is 0, all carbon atoms are connected by single bonds. We can have various structural isomers based on the position of the -OH group and the arrangement of carbon chains.

1. **Straight-chain alcohols**:
- Pentan-1-ol
- Pentan-2-ol
- Pentan-3-ol

2. **Branched-chain alcohols**:
- 2-Methylbutan-1-ol
- 3-Methylbutan-1-ol
- 2-Methylbutan-2-ol
- 3-Pentanol

### Step 4: Count the Isomers
Now, let's list the structural isomers:
1. Pentan-1-ol
2. Pentan-2-ol
3. Pentan-3-ol
4. 2-Methylbutan-1-ol
5. 3-Methylbutan-1-ol
6. 2-Methylbutan-2-ol
7. 3-Pentanol

This gives us a total of **7 structural isomers**.

### Final Answer
The total number of structural isomeric alcohols having the molecular formula C5H12O is **7**.

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