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When liquid 'A' is treated with a freshl...

When liquid 'A' is treated with a freshly prepared ammoniacal silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline solid on treatment with sodium hydrogen sulphite. Liquid 'B' also forms a white crystalline solid with sodium hydrogen sulphite but it does not give test with ammoniacal silver nitrate. which of the two liquids is aldehyde? Write the chemical equations of these reactions also.

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To determine which of the two liquids, A or B, is an aldehyde, we need to analyze the information provided about their reactions. ### Step 1: Analyze Liquid A - **Reaction with Ammoniacal Silver Nitrate**: Liquid A gives a bright silver mirror when treated with freshly prepared ammoniacal silver nitrate solution. This indicates that liquid A is likely an aldehyde, as aldehydes can reduce silver ions to metallic silver, producing the silver mirror effect (Tollens' test). **Chemical Equation**: \[ RCHO + [Ag(NH_3)_2]^+ \rightarrow RCOOH + Ag \downarrow + 2NH_3 ...
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