Rearrange the following compounds in the increasing order of their boiling points :
`CH_(3)-CHO,CH_(3)-CH_(2)-OH,CH_(3)-CH_(2)-CH_(3)`

Explanation

Due to extensive intermolecular H-bonding, the b.p. of `CH_(3)CH_(2)OH` is the highest. Now `CH_(3)CHO` is polar while `CH_(3)CH_(2)CH_(3)` is non-polar. Therefore, due to dipole-dipole interactions, the b.p. of `CH_(3)CHO` is higher than that of `CH_(3)CH_(2)CH_(3)`. thus, the b.ps. of the three compounds increase in the order:
`CH_(3)CH_(2)CH_(3) lt CH_(3)CHO lt CH_(3)CH_(2)OH`.