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One mole of a symmetrical alkene on ozon...

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44u. The alkene is:

A

2-butene

B

ethene

C

propene

D

1-butene

Text Solution

Verified by Experts

The correct Answer is:
A
The aldehyde with molecular mass 44u is `CH_(3)CHO` (acetaldehyde). Therefore, the symmetrical alkene is 2-butene
`underset("2-Butene")(CH_(3)CH=CHCH_(3)) underset((ii)Zn//H_(2)O)overset((i)O_(3))to underset("Acetaldehyde (Mol. Mass of =44u)")(2CH_(3)CH=O)`
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