A compound undergoes the following sequence of reactions:
`C_(3)H_(5)N overset("Hydrolysis")to underset((A))(C_(3)H_(6)O_(2)) overset(Cl_(2)//P)to underset((B))(C_(3)H_(5)O_(2)Cl) overset(NH_(3))to underset((C))(C_(3)H_(7)NO_(2))`
The compound C is

Options

A. 1-nitropropane
B. 2-nitropropane
C. 2-aminopropanoic acid
D. 2-hydroxypropanamide.

Explanation

To solve the problem, we will analyze the sequence of reactions step by step.

### Step 1: Identify the starting compound
The starting compound is given as \( C_3H_5N \). This indicates that it is likely a nitrile or an amine. Given the context of the reactions, we can assume it is a nitrile, specifically propionitrile (\( CH_3CH_2CN \)).

### Step 2: Hydrolysis of the nitrile
When propionitrile undergoes hydrolysis, it reacts with water to form a carboxylic acid. The reaction can be represented as follows:

\[ C_3H_5N + H_2O \rightarrow C_3H_6O_2 + NH_3 \]

The product \( C_3H_6O_2 \) is propanoic acid (\( CH_3CH_2COOH \)), which corresponds to compound (A).

### Step 3: Chlorination of the carboxylic acid
Next, propanoic acid undergoes chlorination in the presence of chlorine and phosphorus. This reaction typically results in the formation of an alpha-chloro acid. The reaction can be represented as:

\[ C_3H_6O_2 + Cl_2 \xrightarrow{P} C_3H_5O_2Cl \]

The product \( C_3H_5O_2Cl \) is alpha-chloropropanoic acid (\( CH_2ClCH_2COOH \)), which corresponds to compound (B).

### Step 4: Reaction with ammonia
The final step involves the reaction of alpha-chloropropanoic acid with ammonia (\( NH_3 \)). This reaction leads to the substitution of the chlorine atom by an amino group, resulting in the formation of an amino acid. The reaction can be represented as:

\[ C_3H_5O_2Cl + NH_3 \rightarrow C_3H_7NO_2 \]

The product \( C_3H_7NO_2 \) is 2-aminopropanoic acid, also known as alanine, which corresponds to compound (C).

### Final Answer
The compound C is 2-aminopropanoic acid (alanine), \( C_3H_7NO_2 \).

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