The major product in the reaction of N-phenylbenzamide with `Br_(2)//Fe` is

Options

A.
B.
C.
D.

Explanation

To determine the major product in the reaction of N-phenylbenzamide with Br₂ in the presence of Fe, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of N-Phenylbenzamide**:
- N-Phenylbenzamide consists of a benzene ring attached to an amide group (N-phenyl) and another benzene ring connected to the carbonyl (C=O) of the amide. The structure can be depicted as:
```
C6H5-NH-C(=O)-C6H5
```

2. **Understand the Reaction Conditions**:
- The reaction involves bromination using Br₂ and Fe. Iron (Fe) acts as a catalyst to generate bromonium ions, which are electrophiles that can react with the aromatic ring.

3. **Recognize the Electrophilic Substitution Mechanism**:
- The reaction is an electrophilic aromatic substitution. The amide group (NH) is an electron-donating group due to the lone pair of electrons on nitrogen, which increases the electron density on the aromatic ring.

4. **Determine the Sites of Electrophilic Attack**:
- The electron density is increased at the ortho and para positions relative to the amide group. However, the para position is less hindered sterically compared to the ortho position.

5. **Consider the Effect of the Carbonyl Group**:
- The carbonyl (C=O) of the amide is an electron-withdrawing group, which decreases electron density at the ortho and para positions. However, the electron-donating effect of the NH group is stronger, making the ortho and para positions still reactive.

6. **Predict the Major Product**:
- The major product will be formed at the para position due to less steric hindrance. The product will be para-bromo-N-phenylbenzamide, which can be represented as:
```
C6H5-NH-C(=O)-C6H4Br (where Br is at the para position)
```

### Final Product:
The major product of the reaction of N-phenylbenzamide with Br₂ in the presence of Fe is para-bromo-N-phenylbenzamide.

---