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Statement 1: Esters on reduction with Li...

Statement 1: Esters on reduction with `LiAlH_(4)` give alcohols while amides give primary amines.
Statement 2: Alkoxide ion is a better leaving group than amide ion.

A

Statement-1 is True, statement-2 is true,statement-2 is a correct explanation for statement-1

B

Statement-1 is true, statement-2 is true, statement-2 is not a correct explanation for statement-1

C

Statement-1 is true, statement-2 is false

D

Statement-1 is false, statement-2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements given in the question, we will break down each statement and evaluate their correctness. ### Step 1: Evaluate Statement 1 **Statement 1:** "Esters on reduction with `LiAlH_(4)` give alcohols while amides give primary amines." - **Esters** are compounds with the functional group `RCOOR'`. When esters are reduced using lithium aluminum hydride (`LiAlH4`), they undergo reduction to yield alcohols. The reaction can be represented as: \[ RCOOR' + LiAlH4 \rightarrow RCH2OH + R'OH \] Here, the carbonyl group (C=O) is reduced to a primary alcohol. - **Amides** have the general structure `RCONH2`. When amides are reduced with `LiAlH4`, they yield primary amines. The reaction can be represented as: \[ RCONH2 + LiAlH4 \rightarrow RCH2NH2 \] The carbonyl group is reduced to a primary amine. Thus, Statement 1 is **True**. ### Step 2: Evaluate Statement 2 **Statement 2:** "Alkoxide ion is a better leaving group than amide ion." - An **alkoxide ion** is the conjugate base of an alcohol and has the formula `RO-`. It is a relatively stable ion and can easily leave during nucleophilic substitution reactions. - An **amide ion** is the conjugate base of an amide and has the formula `RCONH-`. The amide ion is a stronger base compared to the alkoxide ion and is less stable as a leaving group. In general, weaker bases are better leaving groups. Since the alkoxide ion is a weaker base than the amide ion, it is indeed a better leaving group. Thus, Statement 2 is **True**. ### Conclusion Both statements are correct. ### Final Answer: - Statement 1 is True: Esters give alcohols, and amides give primary amines upon reduction with `LiAlH4`. - Statement 2 is True: Alkoxide ion is a better leaving group than amide ion. ---
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