When benzenediazonium hydrogen sulphate is warmed with methanol, the product formed is

Options

A. benzene
B. benzenol
C. benzyl alcohol
D. anisole

Answer

To determine the product formed when benzenediazonium hydrogen sulfate is warmed with methanol, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are benzenediazonium hydrogen sulfate (C6H5N2+HSO4-) and methanol (CH3OH).

### Step 2: Understand the Reaction
When benzenediazonium salts are treated with alcohols, a common reaction occurs where the diazonium group (N2+) is replaced by an alkoxy group (in this case, the methoxy group from methanol).

### Step 3: Removal of Nitrogen Gas
Upon warming, the benzenediazonium salt decomposes, releasing nitrogen gas (N2). This step is crucial as it leads to the formation of a reactive intermediate.

### Step 4: Formation of the Product
After the release of nitrogen gas, the remaining phenyl cation (C6H5+) can react with methanol. The methanol donates its -OCH3 group to the phenyl cation, resulting in the formation of anisole (methoxybenzene, C6H5OCH3).

### Step 5: Write the Final Product
The final product formed from the reaction is anisole (C6H5OCH3).

### Summary of the Reaction
The overall reaction can be summarized as:
\[ \text{C}_6\text{H}_5\text{N}_2^+\text{HSO}_4^- + \text{CH}_3\text{OH} \xrightarrow{\text{heat}} \text{C}_6\text{H}_5\text{OCH}_3 + \text{N}_2 + \text{H}_2\text{SO}_4 \]

### Final Answer
The product formed is anisole (C6H5OCH3).

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