Reduction of N-methylacetamide with `LiAlH_(4)` in ether gives_______

Explanation

To solve the question regarding the reduction of N-methylacetamide with lithium aluminum hydride (LiAlH₄) in ether, let's break it down step by step.

### Step-by-Step Solution:

1. **Identify the Reactant:**
- The reactant is N-methylacetamide, which has the structure:
\[
\text{CH}_3\text{C(=O)N(CH}_3\text{)}
...