`C_(5)H_(13)N` reacts with `HNO_(2)` to give an optically active alcohol The compound is

R_(3) N reacts with HNO_(2) to give

An optically active compound [A] C_(5)H_(13)N reacts with alkaline CHCl_(3) to give an optically active, compound [B]. [A] also reacts with nitrous acid to give an optically inactive alcohol [C] C_(5)H_(11)OH as the major product. What would be the structure of [A]?

Assertion: The amine H_(3)C-overset(CH_(3))overset(|)(CH)-underset(NH_(2))underset(|)(C)H-CH_(3) Upon reaction with HNO_2 will give six optically active alcoholic products Reason: During the reaction there is formation of carbocationic intermediate which may rearrange.

Optically active isomer (A) of (C_(5)H_(9)Cl) on treatment with one mole of H_(2) gives an optically inactive compound (B) compound (A) will be :

Optically active amine having molecular formula C_(5)H_(13)N on reaction with NaNO_(2)+HCI produces, 3^(@) optically inative alcohol. Find out structures of amines:

An organic compound (A) C_(9)H_(13)N dissolves in dil. HCI and releases N_(2) with HNO_(2) giving an optically active alcohol. Alcohol ox oxidation gives dicarboxylic acid, which on heating form anhydride. The organic compound 'A' is: