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How do yout explain the presence of five...

How do yout explain the presence of five `-OH` groups in glucose molecule?

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On acetylation with acetic anhydride in presence of pyridine or a few drops of conc. `H_2SO_4`. It is converted into glucose pnetacetate.
`CH_(2)OH-underset("Glucose")((CHOH)_(4))-CHOoverset((CH_3CO)_(2)O //"pyridine")underset("Acetylation")to CH_(3)COOCH_(2)-underset("Glucose pentaacetate")((CHOCOCH_3)_(4))-CHO`
This confirms the presence of five `-OH` groups in glucose molecule.
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Knowledge Check

  • The presence of -CHO group in glucose is confirmed by its:

    A
    reaction with `PCl_(5)`
    B
    reaction by Na-Hg to give S-orbital
    C
    reaction with Fehling solution
    D
    reaction with Tollen's reagent

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