Nylon 6,10 is obtained by condensation polymerization of ...........with ..................

Answer

To solve the question regarding the formation of Nylon 6,10 through condensation polymerization, we can break it down into several steps:

### Step-by-Step Solution:

1. **Identify the Monomers**:
- Nylon 6,10 is formed from two specific monomers. The first monomer is sebacic acid, and the second monomer is hexamethylene diamine.

2. **Chemical Structures of the Monomers**:
- **Sebacic Acid**: The chemical formula for sebacic acid is \( \text{HOOC-(CH}_2)_8\text{-COOH} \). It consists of a long carbon chain with two carboxylic acid groups at each end.
- **Hexamethylene Diamine**: The chemical formula for hexamethylene diamine is \( \text{NH}_2-(CH_2)_6-NH_2 \). It has two amine groups at each end of a six-carbon chain.

3. **Condensation Polymerization Reaction**:
- In condensation polymerization, the reaction occurs between the carboxylic acid group of sebacic acid and the amine group of hexamethylene diamine.
- During this reaction, a molecule of water (H₂O) is eliminated. The hydroxyl group (-OH) from sebacic acid and a hydrogen atom (H) from the amine group of hexamethylene diamine combine to form water.

4. **Formation of Nylon 6,10**:
- The resulting polymer chain will have alternating amide linkages (-CO-NH-) formed from the reaction of the two monomers. The structure of Nylon 6,10 can be represented as:
\[ -\text{CO-(CH}_2)_8-\text{CO-NH-(CH}_2)_6-\text{NH-} \]
- This structure indicates that Nylon 6,10 is a polyamide, specifically formed from the condensation of sebacic acid and hexamethylene diamine.

5. **Final Answer**:
- Therefore, Nylon 6,10 is obtained by the condensation polymerization of **sebacic acid** with **hexamethylene diamine**.