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How many millilitres of 0.5 M H(2)SO(4) ...

How many millilitres of 0.5 M `H_(2)SO_(4)` are needed to dissolve 0.5 g of copper (II) Carbonate ?

Text Solution

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`CuCO_(3)+H_(2)SO_(4)rarr CuSO_(4)+CO_(2)+H_(2)O`
`"1 mole of "CuCO_(3)=63.5+12+48=123.5" g required "H_(2)SO_(4)="1 mole"`
`therefore 0.5 g CuCO_(3)" will required "H_(2)SO_(4)=(1)/(123.5)xx0.5"mole"=(1)/(247)"mole"`
`"0.5 mole of 0.5 M "H_(2)SO_(4)" are present in 1000 mL"`
`therefore" "(1)/(247)" mole of 0.5 M "H_(2)SO_(4)" will be present in "(1000)/(0.5)xx(1)/(247)mL=8.1mL`
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