Calculate the molarity of NaOH in the solution prepared by dissolving its 4 g in enough water to form 250 mL of the solution.

Explanation

`"Molar of the solute(NaOH)"=(4g)/(40gmol^(-1))=0.1mol" "["Moles"=("Mass in g")/("Molar mass in g mol"^(1))]`
Volume of solution = 250 mL = 0.250 L
`"Molarity of the solution" = ("Moles of the solute")/("Volume of the solution in L")=(0.1)/(0.250)=0.4M`