Calculate the mass of iron which will be converted into its oxide `(Fe_(3)O_(4))` by the action of 18 g of steam on it.

Explanation

The chemical equation representing the reaction is :
`underset("= 168 g")underset(3xx56)(3Fe)+underset("= 72 g")underset(4xx18)(4H_(2)O)rarr Fe_(3)O_(4)+4H_(2)`
Thus, 72 g of steam react with 168g of iron
`therefore" 18 g of steam will react with "(168)/(72)xx18="42 g of iron "therefore" Mass of iron required = 42 g"`