Home
Class 12
CHEMISTRY
Gold biscults are available in the marke...

Gold biscults are available in the market which look exactiy similar to gold but actually they are not of pure gold (but of gold called fool's gold). How will check it by some simple physical property? Density of pure gold is well known to be 19.3 g `cm^(-3)`.

Text Solution

Verified by Experts

We can find out the exact mass and volume* of the given gold bisult and then calculate its density. If it is not made of pure gold, its density will come out to be different from that of pure gold.
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise PROBLEMS FOR PRACTICE|115 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise ADVANCED PROBLEMS (FOR COMPETITIONS)|17 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise Example|2 Videos
  • SOLUTIONS

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|31 Videos
  • SURFACE CHEMISTRY

    PRADEEP|Exercise IMPORTANT QUESTIONS (FOR BOARD EXAMINATION)|28 Videos

Similar Questions

Explore conceptually related problems

Find the mass of 1m^(3) of gold in kg when density of gold is 19 gcm^(-3)

Find thhe mass of 1 m^(3) of gold in kg when density of gold is 19 g cm^(-3) .

A piece of gold weighs 10g in air and 9g in water. What is the volume of cavity? (Density of gold = 19.3 g cm^(-3) )

Which mineral is also known as 'fool's gold'?

Fool's gold is so called because it bears a visual similarity to real gold. A block of fool's gold which measures 1.50 cm xx 2.50 cm xx 3.00 cm has a mass of 56.25 g . How can this material be distinguished from real gold by means of some physical property ? (Given density of real gold = 19.3 g cm^(-3) )

The per cent of pure gold in 14 carat gold is about 58.3%. A 14 carat gold ring weighs 7.6 grams. How many grams of pure gold are in the ring?

The density of gold is 19 g //cm^(2) . Find the volume of 95 g of gold.