2.16 of copper metal when treated with nitric acid followed by ignition of the nitrate gave 2.70 g of copper oxide. In another experiment 1.15 g of copper oxide upon reduction with hydrogen gave 0.92 g of copper. Show that the above data illustrate the Law of Definite Proportions.

Explanation

`%" of Cu in copper oxide in 1st case"=(2.16)/(2.70)xx100=80%`
`%" of oxygen"=20%`
`%" of Cu in copper oxide in 2nd case"=(0.92)/(1.15)xx100=80%`
`%" of oxgyen"=20%`