To account for atomic mass of nitrogen as 14.0067, what should be the ratio of `.^(15)N` and `.^(14)N` atoms in natural nitrogen? (atomic mass of `.^(14)N=14.00307` u and `.^(15)N=15.001u`)

Explanation

To find the ratio of nitrogen-15 (\(^{15}N\)) and nitrogen-14 (\(^{14}N\)) atoms in natural nitrogen, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Values**:
- Atomic mass of \(^{14}N\) = 14.00307 u
- Atomic mass of \(^{15}N\) = 15.001 u
- Average atomic mass of nitrogen = 14.0067 u
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