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The mass of carbon present in 0.5 mole o...

The mass of carbon present in 0.5 mole of `K_(4)[Fe(CN)_(6)]` is -

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The correct Answer is:
36 g
1 mole of `K_(4)[Fe(CN)_(6)]` contains C = 6 g atom
0.5 mole of `K_(4)[Fe(CN)_(6)]` will contain `C=6xx0.5` g atoms = 3 g atoms `=3xx12 g =36`
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