A sample of `NaNO_(3)` weighing `0.38 g` is placed in a `50.0 mL` volumetric flask. The flask is then filled with water to the mark on the neck. What is the molarity of the solution?

Answer

0.090 M

Explanation

Formula mass of `NaNO_(3)=23+14+48=85`
`0.38g NaNO_(3)=23+14+48=85`
`0.38g NaNO_(3)=(0.38)/(85)mol=0.0045mol`
`"Molarity of the solution "=(0.0045mol)/(0.050L)=0.090M.`