In a reaction vessel `0.184 g` of `NaOH` is required to be added for completing the reaction. How many millilitre of `0.150M NaOH` solution should be added for this requirements?

Answer

30.7 mL

Explanation

1000 mL of 0.150 M NaOH contain NaOH = 0.150 mol `=0.150xx40=6g`
i.e., For 6 g in 0.150 M M NaOH solution, volume of solution `-=" 1000 mL"`
`therefore" For 0.184 g in 0.150 M NaOH solution, volume "-=(1000)/(6)xx0.184=30.7mL`