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The concentration of H(2)SO(4) in a bota...

The concentration of `H_(2)SO_(4)` in a botal labelled ''conc. Sulphuric acid'' is 18 M. The solution has a density of `"1.84 g cm"^(-3)`. What is the mole fraction and weight percentage of `H_(2)SO_(4)` in this solution?

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Verified by Experts

`"Conc. = 18 mol L"^(1)`. Solute = 18 moles `=18xx98g=1764g`, Solution = 1000 `cm^(3)` = 1840 g.
Solvent = `1840 - 1764 = 76 g`
`"Mole fraction of "H_(2)SO_(4)=(18)/(76//18+18)=0.81" , Weight"%=(1764)/(1840)xx1000=95.87.`
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