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Calculate the molality of 1 litre soluti...

Calculate the molality of 1 litre solution of 93% `H_(2)SO_(4) ("weight"//"volume")`. The density of solution is 1.84 g `mL^(-1)`.

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`93%H_(2)SO_(4)(w//v)=93gH_(2)SO_(4)` in `100cm^(3)` of the solution = 93 g in 184 g of the solution
`therefore" Solvent (water )"=184-93=91g=0.091kg" , Molality"=(93//98mol)/(0.091kg)=10.43m.`
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