Find out the volume of Cl(2) at STP prod...

Find out the volume of `Cl_(2)` at STP produced by the action of 100 `cm^(3)` of `0.2N` HCl on excess of `MnO_(2)`.

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Verified by Experts

The correct Answer is:

`112cm^(3)`

`MnO_(2)+underset(4xx36.5g)(4HCl)rarrMnCl_(2)+2H_(2)O+underset(22400cm^(3)" at STP")(Cl_(2))`
`"HCl present in "100cm^(3)" of 0.2 N HCl"=(0.2)/(1000)xx"100g eq.= 0.02g eq."xx"36.5 g = 0.73 g"`

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