A plant virus is found to consist of uniform cylindrical particle of `150 Å` in diameter 5000 Å long. The specific volume of the virus is 0.75 `mLg^(-1)`. If the virus is considered to be a single particle, find its molar mass.

Explanation

`"Volume of one virus particle"=pir^(2)h=(22)/(7)xx((150)/(2)xx10^(-8)cm)^(2)xx(5000xx10^(-8)cm)=8.839xx10^(-17)cm^(3)`
`"Mass of one virus particle "=8.839xx10^(-17)cm^(3)xx(1g)/(0.75cm^(3))=(11.785xx10^(-17))g`
`therefore" Molar mass (i.e. mass of Avogadro's no. of particles)"=(11.785xx10^(-17))xx(6.022xx10^(23))`
`=7.098xx10^(7)" g mol"^(-1)`.