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How much of NaOH is required to neutrali...

How much of NaOH is required to neutralise 1500 `cm^(3)` of `0.1` M HCl?

A

40 g

B

4 g

C

6 g

D

60 g

Text Solution

Verified by Experts

The correct Answer is:
C
`1500cm^(3)" of of 0.1 N HCl"-=(0.1)/(1000)xx1500="0.15 g eq."`
It will neutralise `NaOH=0.15" g eq."=0.15xx40g=6g`
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