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The volume of water to be added to 100 c...

The volume of water to be added to `100 cm^(3)` of `0.5 NH_(2)SO_(4)` to get decinormal concentration is

A

`100cm^(3)`

B

`450cm^(3)`

C

`500cm^(3)`

D

`400cm^(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(1)V_(1)=N_(2)V_(2)", i.e., "0.5xx100=0.1xxV_(2)or V_(2)=500cm^(3)`
`therefore" Water to be added to "100cm^(3)" solution"=500-100=400cm^(3).`
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