`100 mL` of phosphine `(PH_(3))` on hearing forms phosphorous `(P)` and hydrogen `(H_(2))`. The volume change in the reaction is

Options

A. an increase of 50 ml
B. an increase of 100 ml
C. an increase of 150 ml
D. a decrease of 50 ml

Answer

A

Explanation

`underset("2 mL")(2PH_(3))(g)rarr2P(s)+underset("3 mL")(3H_(2)(g))`
2 mL `PH_(3)` on decomposition give 3 mL of `H_(2)`, i.e., increase = 1 mL
`therefore " 100 mL PH"_(3)" will result in increase = 50 mL"`