Calculate the mass precent of different elements present in sodium sulphate `(Na_(2)SO_(4))`.

Explanation

`"Mass "%" of an element"=("Mass of that element in the compound")/("Molar mass of the compound")xx100`
`"Now, molar mass of "Na_(2)SO_(4)=2(23.0)+32.0+4xx16.0="142 g mol"^(-1)`
`"Mass percent of sodium"=(46)/(142)xx100=32.39%`
`"Mass per cent of sulphur"=(32)/(142)xx100=22.54%`
`"Mass per cent of oxygen"=(64)/(142)xx100=45.07%`