Calculate the concentration of nitric acid in moles per litre in a sample which has a density `1.41 g //mL` and the mass percent of nitric acid in it being `69%`.

Explanation

Mass percent of `69%` means that 100 g of nitric acid solution contain 69 g of nitric acid by mass.
Molar mass of nitric acid `(HNO_(3))=1+14+48=63gmol^(-1)`
`therefore" Moles in 69 g "HNO_(3)=(69g)/(63gmol^(-1))=1.095" mole"`
`"Volume of 100 g nitirc acid solution"=(100g)/(1.41g mL^(-1))=70.92mL=0.07092L`
`therefore" Conc. of "HNO_(3)" in moles per litre"=("1.095 mole")/("0.07092 L")=15.44M`