What is the concentration of sugar `(C_(12)H_(22)O_(11))` in `mol L^(-1)` if its `20 g` are dissolved in enough water to make a final volume up to `2L`?

Explanation

Molar mass of sugar `(C_(12)H_(22)O_(11))=12xx12+22xx1+11xx16=342gmol^(-1)`
`"No. of moles in 20 g of sugar "=(20g)/(342gmol^(-1))=0.0585 " mole"`
`"Volume of solution = 2 L (Given)"`
`"Molar conentraction "=("Moles of solute")/("Volume of sol in L")=(0.0585mol)/(2L)=0.0293molL^(-1)`
`=0.0293M`