The following data are obtained when dinitrogen and dioxygen react to gether to form different compounds:
`{:(,,"Mass of dinitrogen",,"Mass of dioxygen"),(i.,,14 g,,16 g),(ii.,,14 g,,32 g),(iii.,,28 g,,32 g),(iv.,,28 g,,80 g):}`
a. Which law of chemical combination is obeyed by the above experimental data? Give its statement.
d. Fill in the blanks in the following conversions:
I. `1 km`= ....... mm= ......pm
II. `1 mg=` ........ `kg=` ......... ng
III. `1 mL`= ........ L= ......... `dm^(3)`

Explanation

(a) Fixing the mass of dinitrogen as 28 g, masses of dioxygen combined will be 32, 64, 32 and 80 g in the given four oxides. These are in the ratio `2:4:2:5` which is a simple whole number ratio. Hence, the given data obey the law of multiple proportions.
(b) `"1 km = 1 km"xx(1000m)/(1km)xx(100cm)/(1m)xx(10mm)/(1cm)=10^(6)mm`
`1 km=1km xx(1000m)/(1km)xx("1 pm")/(10^(-12)m)=10^(15)" pm"`
(ii) `1mg=1mgxx(1g)/(1000mg)xx(1kg)/(1000g)=10^(-6)kg`
`1mg=1mgxx(1g)/(1000mg)xx(1ng)/(10^(-9)g)=10^(6)ng`
(iii) `1mL=1mLxx(1L)/(1000mL)=10^(-3)L`
`mL=1cm^(3)=1cm^(3)xx(1dmxx1dmxx1dm)/(10cmxx10cmxx10cm)=10^(-3)dm^(3)`