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How are 0.50 mol Na(2)CO(3) and 0.50 M N...

How are `0.50 mol Na_(2)CO_(3)` and `0.50 M Na_(2)CO_(3)` different?

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`"Molar mass of "Na_(2)CO_(3)=2xx23+12+3xx16=106gmol^(-1)`
`"0.50 mol "Na_(2)CO_(2)" means "0.50xx106g=53g`
`"0.50 M "Na_(2)CO_(3)" means 0.50 mol, i.e., 53 g "Na_(2)CO_(3)" are present in 1 litre of the solution"`
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