One mole of any substance contains `6.022 xx 10^(23)` atoms/molecules. Number of molecules of `H_(2)SO_(4)` present in 100 mL of 0.02 M `H_(2)SO_(4)` solution is :

Options

A. `12.044xx10^(20)" molecules"`
B. `6.022xx10^(23)" molecules"`
C. `1xx10^(23)" molecules"`
D. `12.044xx10^(23)" molecules."`

Answer

A

Explanation

`"1000 mL of 1 M "H_(2)SO_(4)" contain = 1 mole of "H_(2)SO_(4)`
`"100 mL of 0.02 M "H_(2)SO_(4)" contain "H_(2)SO_(4)=(1)/(1000)xx100xx0.02" mole"=0.002" mole"=2xx10^(-3)" mole"`
`=2xx10^(-3)xx(6.022xx10^(23))" molecules"=12.044xx10^(20)" molecules."`