`25cm^(3)` of 0.2 M solution of metal chloride `(MCl_(x))` reacted with `150cm^(3)` of 0.1 M `AgNO_(3)` solution completely to form the precipitate of AgCl. What is the formula of metal chloride ?

Explanation

To determine the formula of the metal chloride \( MCl_x \) that reacts with silver nitrate \( AgNO_3 \) to form silver chloride \( AgCl \), we can follow these steps:

### Step 1: Calculate the number of millimoles of \( MCl_x \)
Given:
- Volume of \( MCl_x \) solution = 25 cm³ = 25 mL
- Molarity of \( MCl_x \) = 0.2 M

Using the formula for millimoles:
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