Home
Class 12
CHEMISTRY
Naturally occurring boron consists of ...

Naturally occurring boron consists of two isotopes whose atomic weight are `10.01 and 11.01 `. The atomic weight of the natural boron is `10.81 `. Calculate the percentage of each isotopes in natural boron.

Promotional Banner

Topper's Solved these Questions

  • APPENDIX

    PRADEEP|Exercise MODEL TEST PAPER <br> (Section B)|8 Videos
  • ALDEHYDES, KETONES AND CARBOXYLIC ACIDS

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|29 Videos
  • BIOMOLECULES

    PRADEEP|Exercise IMPORTANT QUESTIONS (FOR BOARD EXAMINATION)|25 Videos

Similar Questions

Explore conceptually related problems

Naturally occureing boron consists of two insotopes whose atomic weight are 10.01 and 11.01 The atomic weight of the natural boron is 10.81 Calkculate the precentage of e ach isotopes in natURAL BORON

Nuturally occurring boron consists of two isotopes whese atomic weight are 10.01 and 11.01 The atomic weight of nurons is 10.81 Calculate the percentage of each isotope is natural boron

Boron has two isotopes, B-10 and B-11. The average atomic mass of boron is found to be 10.80u. Calculate the percentage of abundance of these isotopes.

boron has two isotopes B-10,B-11. The average atomic mass of boron is found to be 10.80u. Calculate the percentage abundance of B^(10) isotope :-

Atomic weight of chlorine is 35.5 . It has two isotopes of atomic weight 35 and 37 . What is the percentage of the heavier isotope in the sample ?

In nature, ratio of isotopes Boron, ""_5B^(10) and ""_5B^(11) , is (given that atomic weight of boron is 10.81)