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Calculate the percentage of oxalate ions...

Calculate the percentage of oxalate ions in a given sample of oxalate salt 3.0 of which has been dissolve per litre of the solution 10 mL of the oxalate salt solution required 8 mL of 0.01 M `KMnO_(4)` solution complete oxidation

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The correct Answer is:
0.5867

Balanced chemical equation for the redox reaction is
`2MnO_(4)^(-)+16H^(+)+5C_(2)O_(4)^(2-)rarr2Mn^(2+)+10CO_(2)+8H_(2)O`
applying molaritye equation `(M_(1)xx10)/(5)(C_(2)O_(4)^(2-))=(0.01xx8)/(2)(MnO_(4)^(-)) or M_(1)=0.02` M
Mol wt of `C_(2)O_(4)^(2-)=88`
`%C_(2)O_(4)^(2-)=(1.76xx100)/(3)=58.67`
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