The emf `(E^(@))` of the following cels are :
`Ag|Ag^(+) (1 M)||Cu^(2+) (1 M)|Cu, E^(@)=-0.46` volt
`Zn|Zn^(2+) (1 M)||Cu^(2+) (1 M)|Cu, E^(@)=+1.10` volt
Calculate the emf of the cell :
`Zn|Zn^(2+) (1 M)||Ag^(+) (1 M)|Ag`

Answer

1.56 V

Explanation

`-0.46 =6_(Cu^(2+)A,Cu)^(@)(-E_(Ag)^(+),Ag)`
`1.10 =E_(Cu^(2+),Cu)&^(@)-E_(Zn^(2+),Zn)^(@)`
subtracting Eq (i) form Eq (ii) we have
`E_(Cell)^(@)=1.10-(-0.46)=E_(Ag)^(@),Ag-E_(Zn+Zn)^(@)or 1.56V =E_(ag)^(@),Ag_(E)^(@)(Zn^(2+),Zn)`
In other words `E^(@)` of cell ,`Zn|Zn^(2+)(M)||Ag^(+)(M)|Ag` is 1.56 V