Using stock notation represetn the following comoounds : `HauCI_(2),TI_(2),FeO,F_(2),CuI,CuO,MnO and MnO_(2)`

Explanation

By applying the various rules for determining the oxidation number of diffeeent atoms in a compund the oxidation number of each metallic element in the given compound is a s follows
In `HaucI_(4) Au` ha +3 in `TI_(2)O` TI has +1 , in `FeO,Fe` has +2 in `Fe_(2)O_(3) Fe` has +3 in CuI Cu has +1 in CuCOCu +2 in MnO Mn hs +2 while in `MnO_(2)` Mn has +4 oxidation state therefore these compounds may be repersented as
`Hau(III) CI_(4),TI_(2)O,Fe_(2)(III)O_(3),Cu(I)I,,Cu(II)O` and `Mn(iv)O_(2)`