If the moleucar wt of `Na_(2)S_(2)O_(3)` and `I_(2)` are `M_(1)` and `M_(2)` respectivly then what will be the equivalent wt of `Na_(2)S_(2)O_(3)` and `I_(2)` in the following reaction
`S_(2)O_(3)^(2-)+I_(2)rarrS_(4)O_(6)^(2-)+2I^(-)`

Explanation

` 2Na_(2)S_(2)O_(3)=Na_(2)S_(4)O_(6)`
Total increase is O.N of S for molecules of `Na_(2)S_(2)O_(3)=4xx2.5-2[2(+2)]=2`
`therefore` Total increase in O.N of S per molecule of `Na_(2)S_(2)O_(3)=1`
`therefore` Eq mass =`M_(1)//1=M_(1)`
now `I_(2)^(2)rarrr2I^(-1)`
Total decrease is O.N per molecule of `I_(2)=0-2(-1)=2`
`therefore` Eq mass of `I_(2)=M_(2)//2`