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Acidified K(2)Cr(2)O(7) solution turns g...

Acidified `K_(2)Cr_(2)O_(7)` solution turns green when `Na_(2)SO_(3)` is added to it. This is due to the formation of

A

`Cr_(2)(SO_(4))_(3)`

B

`CrO_(4)^(2-)`

C

`Cr_(2)(SO_(3))_(3)`

D

`CrSO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
a

`K_(2)Cr_(2)O_(7)//H_(2)SO_(54)` xoddieses `Na_(2)SO_(3)` to `Na_(2)SO_(54)` and itself gets reduced to `Cr_(2)(SO_(4)^(3))`
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