When `CI_(2)` gas reacts with hot and concentrated sodium hydroxide solution ,the oxidation number of chlorine changes from:

Options

A. zero to +1 and zero to -5
B. zero to -1 and zero to +5
C. zero to -1 and zero +3
D. zero to +1 and zero to -3

Answer

b

Explanation

`3overset(+1)CIOrarroverset(+5)CIO_(3)^(-)+2overset(-1)CI^(-)`
Here O.N of CI increases from +1 CIO to +5 in `CIO_(3)^(-)` while that of CI decrease form +1 in `CIO_(3)^(-)` while that of CI decreses form +1 in `CIO^(-)` to -1 `CI^(-)` therefore it is a disproportionation reaction