In the following redox reaction,
`xUO^(2+)+Cr_(2)O_(7)^(2-)+yH^(+)toaUO_(2)^(2+)+zCr^(3+)+bH_(2)O`
the value of coefficients x,y and z respectively, are

Options

A. 3,8,2
B. 3,8,7
C. 3,2,4
D. 3,1,8

Answer

a

Explanation

balanced oxidaton half reaction is
`YO^(2+)+H_(2)OrarrUO_(2)^(2+)+2H^(+)+2e^(-)`
balanced reduction half reaction is
`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr2Cr^(3+)+7H_(2)O`..(ii)
Multiply Eq (i) by 3 and add to Eq (ii) we have
`3UO^(2+)_+Cr_(2)O_(7)^(2-)+8H^(+)rarr3UO_(2)^(2+)+2Cr^(3+)+4H_(2)O`
Thus Eq (iii) represented balanced redox reaction equation therefore coefficients are x=3,y=8 and z=2 i.e option (a) is correct