How many mL of 0.125 M `Cr^(3+)` must be rected with 12.00 mL of 0.200 M `MnO_(4)^(-)` if the redox products are `Cr_(2)O_(7)^(2-)` and `Mn^(2+)` ?

Options

A. 8 mL
B. 16 mL
C. 24 mL
D. 32 mL

Answer

d

Explanation

Reduction equation
oxidation equation
`2Cr^(3+)+7_(2)OrarrCr_(2)O_(7)^(2-)+14H^(+)+6e^(-)xx5`
balanced redox equation
applying molarity equation
`therefore (0.125xxV)/(10)=(0.2000xx12.00)/(6)`
or `V_(1)=(0.200xx12.00)/(6)xx(10)/(0.125)=32 mL`