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Two electrochemical cell Zn|Zn^(2+)||C...

Two electrochemical cell
`Zn|Zn^(2+)||Cu^(2+)|Cu` and `Fe |Fe^(2+)|Cu^(2+)|Cu` are connected in series what will be the net e.m.f of the cell at `25^(@)C` ?
Give : `Zn^(2+)|Zn=-0.76 V`
`Cu^(2+)|Cu=+0.34 v,Fe^(2+)|Fe=-0.41V`

A

`+1.85 V`

B

`-1.85 V`

C

`+0.83 V`

D

`-0.83 V`

Text Solution

Verified by Experts

The correct Answer is:
a
EMF for the cell `Zn|Zn^(2+)|Cu^(2+)|Cu=0.34-(-0.76)=0.75V`
since the two cells are connected in series therefore the net EMF of the two cells
=1.10 +0.75 =1.85 V
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