The emf of the cell involving the following reaction, `2Ag^(+) +H_(2) rarr 2Ag +2H^(+)` is `0.80` volt. The standard oxidation potential of silver electrode is:-

Options

A. `-0.80` volt
B. 0.80 volt
C. 0.40 volt
D. `-0.40` volt

Answer

a

Explanation

Since `E_(2H^(+)//H_(2))^(@)=0V and E_(Ag^(+)//Ag)^(@)=+0.80 V`
therefore `E_(2H^(+)//H_(2))^(@)` acts as the anode and
`Ag^(+)//Ag` acts as the cathode and the
`E_(cell)^(@)=E_(cathode)^(@)-E_(anode)^(@)`
=0-(+0.80)=-0.80 V