The total surface area of a hollow cylinder, which is open from both sides is 3575 `cm^2`, area of the base ring is 357.5 `cm^2` and height is 14 cm. Find the thickness of the cylinder .

Explanation

TSA=CSA of inside cylinder+CSA of outside cylinder+2*area of ring

`3575=2piR_1h+2piR_2h+2pi(R_2^2-R_1^2)`

`3575=2[14pi(R_1+R_2)+357.5]`

`R_1+R_2=(3575-715)/(28pi)`

`pi(R_2^2-R_1^2)=357.5`

`pi(3575-715)/(28pi)*(R_2-R_1)=357.5`

`R_2-R_1=228/8=7/2=3.5cm`.