The median of the following data is 525. Find the values of `x` and `y` , if the total frequency is 100 Class interval Frequency 0 100 2 100 200 5 200 300 `x` 300 400 12 400 500 17 500 600 20 600 700 `y` 700 800 9 800 900 7 900 1000 4

The median of the following dats is 52.5. If the total frequency is 100, find the value of x and y

The median of the following data is 525. Find the missing frequency, if it is given that there are 100 observations in the data: Class interval Frequency Class interval Frequency 0 100 2 500 600 20 100 200 5 600 700 f_2 200 300 f_1 700 800 9 300 400 12 800 900 7 400 500 17 900 1000 4

If the median of the following frequency distribution is 525, in the table given below, find the value of x and y. if total frequency is 100.

If the median of the following data is 32.5, find the missing frequencies. Class interval: 0-10 10-20 20-30 30-40 40-50 50-60 60-70 Total Frequency: f_1 5 9 12 f_2 3 2 40

If the mean of the following data is 26, then find the missing frequency x. {:("Class Interval",f),(" "0-10,4),(" "10-20,X),(" "20-30,9),(" "30-40,5),(" "40-50,6):}

Find the mean deviation from the mean for the following data: Classes 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 Frequencies 4 8 9 10 7 5 4 3

Find the mean deviation about the mean for the data : Income 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 per day Number 4 8 9 10 7 5 4 3 of persons

Find the median of the following data: class : 0-10 , frequency :5 , 10-20 , 3 , 20-30 , 4 , 30-40 , 3 , 40-50 , 3, 50-60 , 4, 60-70 , 7 , 70-80 , 9 , 80-90 , 7 , 90-100 , 8 ,

A frequency distribution of the life times of 400 T.V. picture tubes tested in a tube company is given below. Find the average life of tube. Life Time (in hrs) Frequency Life time (in hrs) Frequency 300-399 400-499 500-599 600-699 700-799 14 46 58 76 68 800-899 900-999 1000-1099 1100-1199 62 48 22 6