Find: `(4-1/n)+(7-2/n) +(10-3/n) ...` upto n terms

Find the sum (1-1/n)+(1-2/n)+(1-3/n) +........upto n terms.

(1-1/n) + (1 - 2/n) + (1 - 3/n)+ …… upto n terms = ?

Find the sum, (i) 4-(1)/(n)+4-(2)/(n)+4-(3)/(n) …………upto n terms (ii) 1+(-2)+(-5)+….+(-236) .

The odd value of n for which 704 + 1/2 (704) + 1/4 (704) + ... upto n terms = 1984 - 1/2 (1984) + 1/4 ( 1984) - .... upto n terms is :

Find the sum of 1^1 n + 2^2 (n - 1) + 3^2 (n - 2) + 4^2 (n -3) ……upto 'n' terms.

2.4 + 4.7 + 6.10+ …. upto (n-1) terms=

If (1 + 3 + 5 + .... " upto n terms ")/(4 + 7 + 10 + ... " upto n terms") = (20)/(7 " log"_(10)x) and n = log_(10)x + log_(10) x^((1)/(2)) + log_(10) x^((1)/(4)) + log_(10) x^((1)/(8)) + ... + oo , then x is equal to

If (1 + 3 + 5 + .... " upto n terms ")/(4 + 7 + 10 + ... " upto n terms") = (20)/(7 " log"_(10)x) and n = log_(10)x + log_(10) x^((1)/(2)) + log_(10) x^((1)/(4)) + log_(10) x^((1)/(8)) + ... + oo , then x is equal to